Python Django TypeError context must be a dict rather than Context is an error which occurs when you try passing a Context instance in Django.
My goal today is to provide a clear and detailed explanation of why this error is happening and how to solve it, we will also check out other ways to get rid of this problem for good.
Exploring the Error : Python Django TypeError context must be a dict rather than Context
This is an error which occurs when you try passing a Context instance in Django.
Please check out the error message bellow and make sure you have the same message.
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TypeError context must be a dict rather than Context.
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Bellow, I am going to explain the cause of the problem and propose multiple different solutions.
The Method that solved my issue : Alternative to passing a Context instance in Django
There are a few options you can use to solve this issue, You can return the result as a dict by using flatten()
You can replace context by context.flatten()
Use return like this
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return t.render(context.flatten())
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Instead of using return t.render(context)
Another option is to use render_to_string
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var = render_to_string('contact/mycode.html', context)
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Keep in mind that you should import render_to_string from django.template.loader
You can opt to not use a Context instance and use a regular dict instead
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var = get_template('contact/mycode.html').render(context)
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Also, make sure to not use Context(), because Context() is deprecated.
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return t.render(Context(Context))
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I hope the options above have fixed your issue, thank you for reading this blog post to the end, good luck with your python projects.
Summing-up :
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Thank you for reading my blog post to the end, If you want to learn more about the Python programming language, check out the official Python Documentation : https://docs.python.org/3/